Answer:
Total
time in going and coming back \[T=\frac{6}{2.5}+\frac{6}{4}\]; total distance
travelled, \[s=\text{6}+\text{6}=\text{12km}\];
Average speed \[=\frac{S}{T}=\frac{12}{\left(
6/2.5 \right)+\left( 6/4 \right)}=\frac{40}{13}km\,{{h}^{-1}}\]
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