Answer:
Since\[{{\text{A}}^{\text{2}}}+{{\text{B}}^{\text{2}}}={{\text{C}}^{\text{2}}}\];
therefore angle between \[\vec{A}\]and \[\vec{B}\] is\[\text{9}0{}^\circ \]. Let
\[\theta \]be the angle between \[\vec{A}\]and\[\vec{C}\], then\[\text{cos}\theta
=\text{3}/\text{5}\]or \[\theta =\text{co}{{\text{s}}^{-\text{1}}}\left(
\text{3}/\text{5} \right)\].
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