Answer:
Yes.\[\vec{A}+\,\vec{B}\]is
represented by the diagonal of the parallelogram drawn whose two adjacent sides
are represented by two vectors and the diagonal passes through the common tail
of \[\vec{A}\]and\[\vec{B}\]. Whereas \[\vec{A}-\,\vec{B}\]is represented by
the diagonal of the same parallelogram but not passing through the common tail
of \[\vec{A}\]and\[\vec{B}\].
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