Answer:
Here,\[\text{u
}=0,\text{a}=\text{g}\]; Using the relation \[{{\text{D}}_{\text{n}}}=\text{u
}+\frac{a}{2}\left( \text{2n}-\text{1} \right)\]
we have \[{{\text{D}}_{\text{1}}}:{{\text{D}}_{\text{2}}}:{{\text{D}}_{\text{3}}}=\frac{g}{2}\left(
\text{2}\times \text{1}-\text{1} \right)\text{ }:\frac{g}{2}\left(
\text{2}\times \text{2}-\text{1} \right):\frac{g}{2}\left( \text{2}\times
\text{3}-\text{1} \right)\text{ }=\text{ 1}:\text{3}:\text{5}\]
You need to login to perform this action.
You will be redirected in
3 sec