Answer:
Area of parallelogram =\[|\overset{\to
}{\mathop{A}}\,\times \overset{\to }{\mathop{B}}\,|=ABsin\text{
}\!\!\theta\!\!\text{ =}\frac{1}{2}AB\](Given) \[\therefore \]\[\sin \theta
=\frac{1}{2}=\sin {{30}^{o}}\]or \[\theta ={{30}^{o}}\]
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