Answer:
Let x be
the displacement at time t of an object in motion. Given, \[\text{x}=\text{k}{{\text{t}}^{\text{3}}}\],
where k is a consant of proportionality.
Velocity of object, \[\text{V}=\frac{dx}{dt}=\text{3k
}{{\text{t}}^{\text{2}}}\]and acceleration of object,\[\text{A}=\frac{dV}{dt}=\text{3k
x 2t }=\text{ 6kt}\]. i.e.\[\text{A}\propto \text{t}\]. It means acceleration \[\propto
\] time.
You need to login to perform this action.
You will be redirected in
3 sec