Answer:
The
magnitude of resultant vector \[\vec{R}\]of two vectors \[\vec{A}\] and \[\vec{B}\]is
given by\[\text{R}=\sqrt{{{A}^{2}}+{{B}^{2}}+2AB\cos \theta }\].
Case (i). R will be maximum if \[\cos \theta =1\] or\[\theta
=0{}^\circ \]. Then\[\text{R}=\sqrt{{{A}^{2}}+{{B}^{2}}+2AB(1)}=\left(
\text{A}+\text{B} \right)\].
Case (ii). R will be minimum if \[\text{cos}\theta
=-\text{1}\]or\[\theta =\text{18}0{}^\circ \]. Then \[\text{R}=\sqrt{{{A}^{2}}+{{B}^{2}}+2AB(-1)}=\left(
\text{A-B} \right)\]or \[\left( \text{B}-\text{A} \right)\]
You need to login to perform this action.
You will be redirected in
3 sec