Answer:
At highest point, velocity of
projectile = \[u\cos \text{ }\!\!\theta\!\!\text{ }\].
K.E. of projectile
at highest point = \[\frac{1}{2}m{{\left( u\,\cos \theta \right)}^{2}}=\left(
\frac{1}{2}m{{u}^{2}} \right){{\cos }^{2}}\theta =T{{\cos }^{2}}\theta \]
You need to login to perform this action.
You will be redirected in
3 sec