Answer:
For hour hand of watch, time period, \[{{T}_{h}}=12h\];
For earth, \[{{T}_{e}}=24h\].
Angular velocity, \[\omega
=\frac{2\pi }{T}\] \[\therefore \]\[\frac{{{\omega
}_{h}}}{{{\omega }_{e}}}=\frac{{{T}_{e}}}{{{T}_{h}}}=\frac{24}{12}=2\] or
\[{{\omega }_{h}}=2{{\omega }_{e}}\]
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