Answer:
K = ? mass = m, length L.
Moment
on inertia of the rod about an axis perpendicular to its length and passing
through the centre is
\[I=\frac{m{{L}^{2}}}{12}\]
Also, \[I=m{{K}^{2}}\] \[\therefore
\] \[m{{K}^{2}}=\frac{m{{L}^{2}}}{12}\] or \[K=\frac{L}{\sqrt{12}}=\frac{L}{2\sqrt{3}}\]
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