Answer:
Here, \[\text{L}=l\omega
\]= constant
\[\therefore \] K.E. of rotation, \[K=\frac{1}{2}I{{\omega
}^{2}}\]
\[K=\frac{1}{2I}{{I}^{2}}{{\omega
}^{2}}=\frac{{{L}^{2}}}{2I}\]
As L is constant, \[\therefore
\] \[K\propto 1/I\]
When moment of inertia (I) decreases, K.E of rotation (K)
increases. Thus K.E. of rotation is not conserved.
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