Answer:
Here,
distance between two consecutive threads = pitch = \[\frac{1}{12}cm\].
Total
distance to be moved = 1.5 cm \[\therefore \] No. of rotations = \[\frac{1.5}{1/12}=18\]
Total
angle of turning, \[\text{ }\!\!\theta\!\!\text{ }=18\times 2\pi =36\pi
\,radian\]
angular
speed, \[\omega =2\pi n=\,2\pi \times \frac{216}{60}=7.2\pi \,rad\,/s\]
\[\therefore
\] time taken, \[t=\frac{\theta }{\omega }=\frac{36\pi }{7.2\pi }=5s\]
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