Answer:
The particle will
leave the hemisphere, when normal reaction R becomes zero. In that event,
\[\frac{m{{\upsilon
}^{2}}}{r}=mg\] \[\therefore \] \[\upsilon
=\sqrt{rg}=\sqrt{\frac{20}{100}\times 9.8}=\sqrt{1.96}=1.4\,m/s\]
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