Answer:
The
vehicle stops when its K.E. is spent in working against the force of friction
between the tyres and the road. This force of friction varies directly with
weight of the vehicle.
As K.E. = work done = force of friction × distance.
\[\therefore \] \[\text{E}=\text{F}\times \text{s}\] or \[\text{s}=\frac{E}{F}\]
For given K.E ; distance s will be smaller, where F is larger,
such as in case of a truck. Therefore, the truck will stop at a lesser
distance.
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