Answer:
(i) The reagents are sodium phenoxide and bromoethane
(i) The reagents are sod. 2-methyl-2-propoxide and bromomethane
\[\underset{Sod.\,2\text{-}methyl\text{-}2\text{-}propoxide}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{C}}\,}}\,-ONa}}\,\,\,\,\,\,+\,\,\,\,\underset{Bromomethane}{\mathop{C{{H}_{3}}-Br}}\,\,\,\,\,\,\xrightarrow{heat}\]\[\underset{2\text{-}Methyl\text{-}2\text{-}methoxypropane}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}}\,-OC{{H}_{3}}+NaBr}}\,\]
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