Answer:
Carbon does not have d-orbitals and
hence does not form d\[\pi \]-p\[\pi \] bonds. In contrast, silicon has empty d-orbitals
and hence it forms d\[\pi \] -p\[\pi \] bonds with oxygen. As a result,
transference of electrons occurs from\[O\] to Si. In other words,
electron-density around O decreases. It, therefore, withdraws electrons of the \[O-H\]
bond towards it. Consequently, \[O-H\] bond in \[{{(C{{H}_{3}})}_{3}}SiOH\]
breaks more easily than in \[{{(C{{H}_{3}})}_{3}}COH\] and hence \[{{(C{{H}_{3}})}_{3}}SiOH\]
is more acidic than\[{{(C{{H}_{3}})}_{3}}COH.\]
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