Answer:
The rate law is given by the
slow step.
\[\therefore \] Rate \[={{k}_{1}}[]N{{O}_{3}}]\,[NO]\]
The equilibrium constant (K) as
predicted by the fast step is:
\[K=\frac{[N{{O}_{3}}]}{[NO]\,[{{O}_{2}}]}\]
or \[[N{{O}_{3}}]\,=K[NO]\,[{{O}_{2}}]\]
Substituting the value of [N03]
in eqn. (i)
Rate
\[(\text{Here}\,k'={{k}_{1}}K')\]
Order of reaction =2+1=3
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