Answer:
1-bromo-1-phenylethane is a secondary alkyl halide while the other is of primary nature. The alkene is expected to be formed by \[{{E}_{2}}\] elimination reaction. In this reaction, secondary alkyl halide is expected to give the desired alkene.
\[\underset{\text{1-Bromo-1-phenylethane}}{\mathop{{{H}_{5}}{{C}_{6}}-\underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\mathop{C}}\,H-C{{H}_{3}}}}\,+KOH\,\,\text{(alc}\text{.)}\xrightarrow{\,}\] \[\underset{\text{Styrene}}{\mathop{{{C}_{6}}{{H}_{5}}-CH=C{{H}_{2}}}}\,+KBr+{{H}_{2}}O\]
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