Answer:
In \[{{S}_{{{N}^{1}}}}\] reaction, a carbocation intermediate is formed in the slow or rate determining step by the cleavage of \[C-Cl\] bond. Now, the cyclopropyl carbocation intermediate is less stable than cyclopentyl carbocation due to greater strain. Therefore, cyclopropyl chloride is less reactive than cyclopentyl chloride towards \[{{S}_{{{N}^{1}}}}\] reaction.
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