Answer:
(a) \[C{{H}_{3}}I\]will react faster
since \[C-I\] bond can cleave more easily as compared to C?Br bond.
(b) \[C{{H}_{3}}Br\]will react faster
because less steric hindrance as compared to \[{{(C{{H}_{3}})}_{3}}CBr\].
(c) \[C{{H}_{2}}CH-C{{H}_{2}}Br\]
will react faster because in \[C{{H}_{2}}=CHBr\] molecule, \[C-Br\] bond has a
partial double bond character due to resonance and its cleavage is more difficult
as compared to \[C{{H}_{2}}=CH-C{{H}_{2}}-Br\] in which the bond does not have partial
double bond character.
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