Answer:
As the size of the alkyl group
increases, \[{{S}_{N}}2\] reactivity decreases. Further, \[C-Br\] bond being
weaker is easier to break than \[C-Cl\] bond. Therefore, the overall increasing
\[{{S}_{N}}2\] reactivity follows the order :
\[{{(C{{H}_{3}})}_{2}}CHCl<C{{H}_{3}}C{{H}_{2}}Cl<C{{H}_{3}}Cl<C{{H}_{3}}Br.\]
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