Answer:
Let us calculate the observed molar
mass of sulphur in the colloidal solution with the help of Van't Hoff equation:
\[\pi =\,\frac{{{W}_{B}}RT}{{{M}_{B}}V}\,\,\,\,or\,\,\,\,{{M}_{B}}\,=\frac{{{W}_{B}}RT}{\pi
V}\]
\[{{M}_{B}}=\frac{\text{(2}\text{.56g)
}\!\!\times\!\!\text{ (0}\text{.821}\
\text{L}\,\text{atm}\,{{\text{K}}^{\text{-1}}}\,\text{mo}{{\text{l}}^{\text{-1}}}\text{)
}\!\!\times\!\!\text{ (300K)}}{\text{(2}\text{.463}\,\text{atm)}\,\text{
}\!\!\times\!\!\text{
(0}\text{.1}\,\text{L)}}=256\,\,\text{g}\,\text{mo}{{\text{l}}^{\text{-1}}}\]
Gram atomic mass of sulphur \[=32\,g\,mo{{l}^{-1}}\]
\[\therefore \] No. of sulphur atoms associated \[=\frac{(256\,g\,mo{{l}^{-1}})}{(32\,g\,mo{{l}^{-1}})}=8\].
You need to login to perform this action.
You will be redirected in
3 sec