Answer:
\[C{{r}^{2+}}(3{{d}^{4}})\xrightarrow{\,}\,C{{r}^{3+}}(3{{d}^{3}})+{{e}^{-}};\]
\[M{{n}^{3+}}\,(3{{d}^{4}})+{{e}^{-}}\xrightarrow{{}}\,M{{n}^{2+}}(3{{d}^{5}})\]
\[C{{r}^{2+}}\] acts as a reducing agent
due to greater stability of \[C{{r}^{3+}}\] with exactly half-filled \[{{t}_{2g}}\]
level. \[M{{n}^{3+}}\] acts as an oxidising agent due to extra stability of \[M{{n}^{2+}}\]
ion with all half filled d-orbitals.
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