Answer:
The electronic configuration of Sc
(Z = 21); \[Sc(Z=21):\,{{[Ar]}^{18}}\,4{{s}^{2}}\,3{{d}^{1}}\]. The element
exhibits +3 oxidation state in its compounds because by losing the three
electrons, it acquires a noble gas configuration. However, it is still regarded
as a transition element because it has a partially filled d sub-shell.
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