question_answer

Why is \[{{H}_{2}}S\] less acidic than \[{{H}_{2}}Te\]?                                           

Answer:

                \[{{H}_{2}}S\]is less acidic \[({{K}_{a}}=1.0\times {{10}^{-7}})\] than \[{{H}_{2}}Te\,(2.3\times {{10}^{-7}})\] because the cleavage of H-Te bond is easier than that of H-S bond due to its more bond length. Therefore, release of \[{{H}^{+}}\] from \[{{H}_{2}}Te\] takes place more readily than from \[{{H}_{2}}S\] molecule.