Answer:
In \[S{{F}_{4}},\] the sulphur atom
has +4 oxidation state and can extend the same to +6 by accepting electron
pairs from \[{{H}_{2}}O\]molecules. Therefore, it can be hydrolysed. But in \[S{{F}_{6}}\],
the oxidation state of sulphur is already +6 and cannot increase the same any
more. Therefore, it cannot be easily hydrolysed. For chemical reaction, consult
section 7.15 (Chemical properties of oxygen family).
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