Answer:
Sulphur shows +4 and +6 oxidation
states due to the presence of vacant 3d orbitals to which electrons can be
promoted from 3s and 3p filled orbitals. Since oxygen atom does not have 2d
orbitals, no electron promotion is possible in this case. Therefore, oxygen
cannot show + 4 and + 6 oxidation states in compounds. For more details,
consult text part.
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