Answer:
Both N and Bi do not form
pentahalides but due to different reasons. The element N cannot extend its
covalency to five due to the absence of vacant 2d orbitals in the valence
shell. The element Bi does not form pentahalide due to strong inert pair effect
by the valence 6s electrons which are not available for bonding. The element P
does form pentahalides\[(PC{{l}_{5}})\] due to the
availability of 3d orbitals which can participate in the bond formation.
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