Answer:
Dilute \[{{H}_{2}}S{{O}_{4}}\]
behaves as a proton acid and zinc metal displaces hydrogen from the acid.
\[Zn+{{H}_{2}}S{{O}_{4}}\text{(dil)}\xrightarrow{}\,ZnS{{O}_{4}}\,+{{H}_{2}}\]
Concentrated \[{{H}_{2}}S{{O}_{4}}\]
behaves as a strong oxidising agent and itself is reduced to \[S{{O}_{2}}\].
\[Zn+2{{H}_{2}}S{{O}_{4}}\text{(conc}\text{.)}\xrightarrow{\,}\,ZnS{{O}_{4}}+S{{O}_{2}}+2{{H}_{2}}O\]
You need to login to perform this action.
You will be redirected in
3 sec