A) 0.119 kJ
B) 0.109 kJ
C) 0.129 kJ
D) 0.120 kJ
Correct Answer: B
Solution :
\[{{H}_{2}}{{O}_{(l)}}\]⇌ \[{{H}_{2}}{{O}_{(g)}},\,\,\,\Delta S=\frac{\Delta {{H}_{vap}}}{T},\] \[\Delta {{H}_{vap.}}=2.257\,KJ/g\] or \[\Delta {{H}_{vap}}=2.257\times 18\,kJ/mol.\,=40.7\,KJ/mol\] hence, \[\Delta S=\frac{40.7}{373}=0.109\,kJ/mol/K.\]You need to login to perform this action.
You will be redirected in
3 sec