A) ? 2.16 J
B) 12.156 J
C) 2.16 J
D) 101.3 J
Correct Answer: C
Solution :
Here: Change in Volume \[(V)=500-300=200cc=0.2\,litre,\] Pressure \[(P)=0.6\,atm\]and heat liberated (q) = 10J Work done \[(W)=P\Delta V=(0.2\times 0.6)=0.12\,litre-atm\] But \[1\,litre-atm=101.3\,J\]. hence \[W=0.12\times 101.3=12.156\,J\]. We also know that heat is liberated, therefore it would be negative. Thus change in \[\Delta E=q+W=-10+12.16=2.16\,J\].You need to login to perform this action.
You will be redirected in
3 sec