Answer:
(i) Acceleration
= slope of the line of v-t graph
\[=\frac{5}{2}=\frac{10}{4}=\frac{15}{6}=2.5\,\text{m/}{{\text{s}}^{\text{2}}}\]
(ii) The force
acting on the body is given by
\[F=ma=5\times
2.5=12.5\text{N}\]
(iii) \[u=0,\upsilon
=5m/s,t=2s\]
Thus, change
in momentum = mv - mu
\[=5\times 5-5\times
0=25\,\text{kg}\,\text{m/s}\]
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