Answer:
Mass of I
player,\[{{m}_{1}}=60kg\]
Velocity of I
player, \[{{u}_{1}}=5m/s\]
Mass of II
player, \[{{m}_{2}}=55kg\]
Velocity of
II player, \[{{u}_{2}}=-6\,m/s\]
(as
direction of motion is opposite)
On getting
entangled, final mass
M = 60 + 55 =115
kg
Final
velocity, v = ?
As no
external force is acting on the system, so from conservation of momentum
\[{{m}_{1}}{{u}_{1}}+{{m}_{2}}{{u}_{2}}=Mv\]
\[\Rightarrow \]\[(60)(5)+(55)(-6)=115\upsilon
\]
\[\Rightarrow \]\[300-330=115\upsilon \]
or\[\upsilon
=\frac{-30}{115}=-\frac{6}{23}m/s\]
The entangled mass
moves at \[\frac{\text{6}}{\text{23}}\text{m/s}\] towards the first player.
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