question_answer

  A stone is allowed to fall from the top of a tower 100 m high and at the same time another stone is projected vertically upwards from the ground with a velocity of 25 m/s. Calculate when and where the two stones will meet. (g=10 m/s2 )

Answer:

                  Stone 1 initial velocity u = 0 If the stones meet after t second, distance           Stone 2                 Distance,                            (1) or                            or                                                            (1/2) Height above the ground = 100 - 80 = 20 m      (1 /2)