question_answer

  An electron moving with a velocity of x 104 m/s enters into a uniform electric field and acquires a uniform acceleration of 104 m/s2 in the direction of its initial motion. (i) Calculate the time in which the electron would acquire a velocity double of its initial velocity. (ii) How much distance the electron would cover in this time?     Sol. Given, u = 5 x 104 m/s, a = 104 m/s2 (i) (1) (ii)                (2)                                (2)

Answer:

                  (i) 100m as 07'= 100m (ii) Speed of B = Slope of (iii) A and B meet at Q, i.e., 150 m from origin and h after the start. (iv) Speed of y 4 = Slope of (v)Difference between speeds = 75 ? 25 = 50 m/s Speed of both the trains is uniform as s-t graph is a straight line.                          (1 x 5)