Answer:
(i)
OA is a straight line graph between speed and time, and it is sloping upward
from O to A. (1/2)
(ii) AB is a straight line graph between speed and time, which is
parallel to the time axis (.v-axis).
So, AB represents uniform speed. There is no acceleration
from A to B. (1/2)
(iii) BC is a straight line graph between speed and time
which is sloping downwards from B to C.
Therefore, BC represents uniform retardation or negative
acceleration. (1)
(iv) Acceleration of the body as we see from graph line OA
represents it. So, the slope of velocity-time graph OA will give the
acceleration of the body.
Thus, Acceleration = Slope of line
we have, AD = 6 m/s, and OD = 4 s
So, acceleration (1)
(v) The slope of line graph BC represents the
retardation of the body.
So, retardation = Slope of line
we have, BE = 6 m/s, EC = 16 -10 = 6 s
Retardation (1)
(iv)The distance travelled by the body is equal to the area
enclosed between the speed-time graph and time axis.
Distance travelled from A to B = Area under the line AB
and the time axis = Area of rectangle DABE = DA x DE
Here, DA = 6 m/s and DE == 10 - 4 = 6 s Distance travelled
from A to 5 = 6 x 6=36 m (1)
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