Answer:
Given,
initial velocity, u = 36 km/h
\[=36\times
\frac{5}{18}=10\,\text{m/s}\]
Final
velocity, \[\upsilon =72\,km/h=72\times \frac{5}{18}=20\,\text{m/s}\]
And
time, t = 20 s
Acceleration,
\[a=\frac{\upsilon
-u}{t}=\frac{20-10}{20}=0.5\,\text{m/}{{\text{s}}^{\text{2}}}\]
From
third equation of motion, \[s=\frac{{{(20)}^{2}}-{{(10)}^{2}}}{2\times
0.5}=300\,\text{m}\]
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