Answer:
When a stone is thrown vertically upwards, it has some
initial velocity (let u). As the stone goes its velocity goes on decreasing (\[\because
\] it is moving against the gravity) and at the highest point i.e., maximum height)
its velocity become zero. Let the stone takes time t seconds to reach at the
highest point. After that stone begins to fall (with zero initial velocity) and
its velocity goes on increasing (\[\because \] it is moving with the gravity)
and it reaches its initial point of projection with the velocity v in the same
time (with which it was thrown).
So.
Velocity
U
0
-u(2)
Time
0
T
2t
Here, we have taken ?u
because in the upward motion velocity of stone is in upward direction and in the
downward motion, the velocity is in downward direction. The velocity-time graph
for the whole journey is shown below
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