question_answer

Find the total displacement of the body from the following graph

Answer:

                Total displacement = sum of areas \[(\Delta ABF+rect.BCGF+\Delta CDE+rect.CEIG)\] \[=\left[ \frac{1}{2}(AF\times FB)+(BC\times CG) \right.\] \[\left. +\frac{1}{2}(CE\times DJ)+(CG\times GI) \right]\] \[=\left[ \frac{1}{2}(2\times 5)+(4\times 5)+\frac{1}{2}(4\times 5)+5(5\times 4) \right]=55\text{m}\]