Answer:
(i)
Displacement of a particle at time t,
\[s=ut+\frac{1}{2}a{{t}^{2}}\]
At
time (t -1), displacement of a particle
\[s'=u\pm
(-1)+\frac{1}{2}a{{(t-1)}^{2}}\]
\[\therefore
\] Displacement in the last 1 s is \[{{s}_{t}}=s-s'\]
\[=ut+\frac{1}{2}a{{t}^{2}}-\left[
u(t-1)+\frac{1}{2}a{{(t-1)}^{2}} \right]\]
\[=ut+\frac{1}{2}a{{t}^{2}}-ut+u-\frac{1}{2}a{{(t-1)}^{2}}\]
\[=\frac{1}{2}a{{t}^{2}}+u-\frac{1}{2}a{{t}^{2}}\frac{-a}{2}+at\]
\[=u+\frac{a}{2}(1t-1)\]
(ii)At
\[u=2\,m/s,a=1\,m{{s}^{2}},t=5s\]
\[s=2+\frac{1}{2}(10-1)=2+4.5=6.5m\]
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