Answer:
(a) Mass number of boron is equal to its atomic mass but
has no unit.
Mass number (A) of boron =11
Number of protons in the nucleus = 5
Atomic number of the element (Z) = 5
Number of neutrons
=A- Z= 11 -5 = 6
(b) Electronic configuration of B = 2,3.
No. of valence electron
in B = 3.
It loses three electrons to form B + ion.
Thus, the configuration of B3+ = 2.
Number of valence electrons
in B + = 2.
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