Answer:
Force applied on road by bpy, F = 5 N
Displacement on the circular path
=One cycle + Half cycle
= 0 + Diameter of circular path = 200 m
Total displacement,
s=1.5 x 1000 + 200 + 2 x 1000
=1500 + 200 + 2000 + 3700 m
Work done = Fs = 5 x 3700 = 18500 J
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