9th Class Science Work and energy Question Bank 9th CBSE Science Work and energy

  • question_answer
                 An automobile engine propels a 1000 kg car along a levelled road at a speed of 36 . Find the power if the opposing frictional force is 100 N. Now, suppose after travelling a distance of 200 m, this car collides with another stationary car (B) of same mass and comes to rest. Let its engine also stop at the same time. Now car (B) starts moving on the same level road without getting its engine started. Find the speed of the car (B) just after the Collision. 

    Answer:

       Mass of car (A) =1000 kg Mass of car (B) = 1000 kg Force applied by car (A) = 100 N Speed of car (A) Power of car (A),P = Fv = 100 x 10 =1000 W  Again         F = ma 100 = 1000 x a From equation of motion,     From conservation of linear momentum,  


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