Answer:
Mass
of a cracker,
Initially, cracker is at rest i.e., u = 0
Therefore, initial momentum of the cracker = mu = 0
(1)
After explosion, mass of each piece
and
Let, velocity of first
piece
velocity of second piece
Momentum of cracker after
explosion
Applying law of conservation of momentum Total final
momentum = Total initial momentumor
The negative sign shows that and
are equal in magnitude and opposite
in direction.
Thus, two pieces of the cracker fly in opposite
directions with same speed.
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