JEE Main & Advanced Physics Alternating Current / प्रत्यावर्ती धारा Question Bank ac Circuits

  • question_answer
    A resistance of 300 W and an inductance of \[\frac{1}{\pi }\] henry are connected in series to a ac voltage of 20 volts and 200 Hz frequency. The phase angle between the voltage and current is                                                         [Roorkee 1980]

    A)            \[{{\tan }^{-1}}\frac{4}{3}\]   

    B)            \[{{\tan }^{-1}}\frac{3}{4}\]

    C)            \[{{\tan }^{-1}}\frac{3}{2}\]   

    D)            \[{{\tan }^{-1}}\frac{2}{5}\]

    Correct Answer: A

    Solution :

                       Phase angle \[\tan \varphi =\frac{\omega L}{R}=\frac{2\pi \times 200}{300}\times \frac{1}{\pi }=\frac{4}{3}\]            \[\therefore \,\,\,\varphi ={{\tan }^{-1}}\frac{4}{3}\]


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