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JEE Main & Advanced Physics Alternating Current / प्रत्यावर्ती धारा Question Bank ac Circuits

  • question_answer
    In a region of uniform magnetic induction \[B={{10}^{-2}}\,tesla\], a circular coil of radius 30 cm and resistance p2 ohm is rotated about an axis which is perpendicular to the direction of B and which forms a diameter of the coil. If the coil rotates at 200 rpm the amplitude of the alternating current induced in the coil is                                               [CBSE PMT 1990]

    A)            4p2 mA                                   

    B)            30 mA

    C)            6 mA                                        

    D)            200 mA

    Correct Answer: C

    Solution :

               Amplitude of \[ac={{i}_{0}}=\frac{{{V}_{0}}}{R}=\frac{\omega NBA}{R}=\frac{(2\pi \nu )NB(\pi {{r}^{2}})}{R}\]            \[\Rightarrow {{i}_{0}}=\frac{2\pi \times \frac{200}{60}\times 1\times {{10}^{-2}}\times \pi \times {{(0.3)}^{2}}}{{{\pi }^{2}}}=6\ mA\]


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