A) 0.32 amp
B) 0.16 amp
C) 048 amp
D) 0.80 amp
Correct Answer: B
Solution :
\[Z=\sqrt{{{R}^{2}}+X_{L}^{2}}\]\[=\sqrt{{{10}^{2}}+{{(2\pi \times 60\times 2)}^{2}}}=753.7\] \[\therefore \,\,i=\frac{120}{753.7}=0.159\,\,A\]
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