2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Alternating Current / प्रत्यावर्ती धारा

JEE Main & Advanced Physics Alternating Current / प्रत्यावर्ती धारा Question Bank ac Circuits

  • question_answer
    If resistance of 100 W , inductance of 0.5 henry and capacitance of \[10\times {{10}^{-6}}F\] are connected in series through 50 Hz ac supply, then impedance is        [BHU 1995]

    A)            1.876                                       

    B)            18.76

    C)            189.72                                     

    D)            101.3

    Correct Answer: C

    Solution :

                       \[Z=\sqrt{{{R}^{2}}+{{({{X}_{L}}-{{X}_{C}})}^{2}}}\]            \[=\sqrt{{{100}^{2}}+{{\left( 0.5\times 100\pi -\frac{1}{10\times {{10}^{-6}}\times 100\pi } \right)}^{2}}}\]\[=189.72\Omega \]


You need to login to perform this action.
You will be redirected in 3 sec spinner