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JEE Main & Advanced Physics Alternating Current / प्रत्यावर्ती धारा Question Bank ac Circuits

  • question_answer
    In a series circuit R = 300 W, L = 0.9 H, C = 2.0 mF and w = 1000 rad/sec. The impedance of the circuit is [MP PMT 1995]

    A)            1300 W                                    

    B)            900 W

    C)            500 W                                      

    D)            400 W

    Correct Answer: C

    Solution :

               For series R-L-C circuit, \[Z=\sqrt{{{R}^{2}}+{{({{X}_{L}}-{{X}_{C}})}^{2}}}\]            \[=\sqrt{{{(300)}^{2}}+{{\left( 1000\times 0.9-\frac{{{10}^{6}}}{1000\times 2} \right)}^{2}}}=500\Omega \]


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