A) \[11.4\,\Omega ,\,17.5\,A\]
B) \[30.7\,\Omega ,\,6.5A\]
C) \[40.4\,\Omega ,\,5\,A\]
D) \[50\,\Omega ,\,4A\]
Correct Answer: D
Solution :
\[Z=\sqrt{{{R}^{2}}+{{X}^{2}}}=\sqrt{{{R}^{2}}+{{(2\pi fL)}^{2}}}\] =\[\sqrt{{{(30)}^{2}}+{{\left( 2\pi \times 50\times \frac{0.4}{\pi } \right)}^{2}}}=\sqrt{900+1600}=50\Omega \] \[i=\frac{V}{Z}=\frac{200}{50}=4\,ampere\]
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